Puzzles And Quizzes

Hi friends here i am glad to propose a new page in blog named "Puzzles And Quizzes" to develop the analytical skills and aptitude skills...


Here i would like to give weekly puzzles and quiz questions. Answer to the puzzles are sent the blogs email id : blogece08@gmail.com
correct answer with appropriate solutions will be sent back.....


THIS WEEK QUESTIONS :-


* There is a 50m long army platoon marching ahead. The last person in the platoon wants to
give a letter to the first person leading the platoon. So while the platoon is marching he
runs ahead, reaches the first person and hands over the letter to him and without stopping
he runs and comes back to his original position.
In the mean time the whole platoon has moved ahead by 50m.
The question is how much distance did the last person cover in that time. Assuming that he
ran the whole distance with uniform speed.
question id : 0001

Answer :- 
The last person covered 120.71 meters.
It is given that the platoon and the last person moved with uniform speed. Also, they both
moved for the identical amount of time. Hence, the ratio of the distance they covered -
while person moving forward and backword - are equal.

Let's assume that when the last person reached the first person, the platoon moved X meters
forward.
Thus, while moving forward the last person moved (50+X) meters whereas the platoon moved X
meters.
Similarly, while moving back the last person moved [50-(50-X)] X meters whereas the platoon
moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total distance covered by the last
person is 100 meters, as he ran the total lenght of the platoon (50 meters) twice. TRUE,
but that's the relative distance covered by the last person i.e. assuming that the platoon
is stationary.
====================================
Let me check how many would able to answer or else think of it
Let me see how many will answer for this question ??? hope for the best

Question No :- 2
A contractor had employed 100 labourers for a flyover construction task. He did not allow
any woman to work without her husband. Also, atleast half the men working came with their
wives.
He paid five rupees per day to each man, four ruppes to each woman and one rupee to each
child. He gave out 200 rupees every evening.
How many men, women and children were working with the constructor?

question id : 0002

ANSWER :-


16 men, 12 women and 72 children were working with the constructor.
Let's assume that there were X men, Y women and Z children working with the constructor.
Hence,
X + Y + Z = 100
5X + 4Y + Z = 200
Eliminating X and Y in turn from these equations, we get
X = 3Z - 200
Y = 300 - 4Z
As if woman works, her husband also works and atleast half the men working came with their
wives; the value of Y lies between X and X/2. Substituting these limiting values in
equations, we get
if Y = X,
300 - 4Z = 3Z - 200
7Z = 500
Z = 500/7 i.e. 71.428
if Y = X/2,
300 - 4Z = (3Z - 200)/2
600 - 8Z = 3Z - 200
11Z = 800
Z = 800/11 i.e. 72.727
But Z must be an integer, hence Z=72. Also, X=16 and Y=12
There were 16 men, 12 women and 72 children working with the constructor.
===================================
Question No :- 3 


Four friends - Arjan, Bhuvan, Guran and Lakha were comparing the number of sheep that they
owned.
It was found that Guran had ten more sheep than Lakha.
If Arjan gave one-third to Bhuvan, and Bhuvan gave a quarter of what he then held to Guran,
who then passed on a fifth of his holding to Lakha, they would all have an equal number of
sheep.
How many sheep did each of them possess? Give the minimal possible answer.



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question id : XXXX

answer :  *************

description about  answers (i.e principle behind the solutions and formulaes required in it)

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